Honors Algebra 2: Extra Practice Solving Rational Equations

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  1. \( \displaystyle \frac{ 2x + 12} { x^2 - 10x + 16} = \frac{ 3} { x - 8} + \frac{ 4} { x - 2} \)
    2. Solution

    10

  2. \( \displaystyle \frac{ 8} { m^2 - 6m} - \frac{ 3} { m - 6} = \frac{ 2} { m} \)
    3. Solution

    4

  3. \( \displaystyle \frac{ 3} { x^2 - 4} + \frac{ 5} { x - 2} = \frac{ 7} { x + 2} \)
    4. Solution

    \( \displaystyle \frac{27}{2} \)

  4. \( \displaystyle \frac{ 8} { y^2 - 7y + 12} = \frac{ 5} { y - 3} + \frac{ 2} { y - 4} \)
    5. Solution

    \( \displaystyle \frac{34}{7}\)

  5. \( \displaystyle \frac{ 2} { b^2 - 5b - 14} = \frac{ 3} { b - 7} - \frac{ 4} { b + 2} \)
    6. Solution

    32

  6. \( \displaystyle \frac{ 4} { a + 3} + \frac{ 2} { 3 - a} = \frac{ 4} { a^2 - 9} \)
    7. Solution

    11

  7. \( \displaystyle \frac{ 4} { p^2 - 8p + 12} = \frac{ p} { p - 2} + \frac{ 1} { p - 6} \)
    8. Solution

    -1

  8. \( \displaystyle \frac{ a + 8} { 16} = \frac{ -2} { a - 10} \)
    9. Solution

    {8, -6}

  9. \( \displaystyle \frac{ x^2 + 7x} { x - 2} = 4 + \frac{ 36} { 2x - 4} \)
    10. Solution

    -5

  10. \( \displaystyle \frac{ y} { y - 2} - 1 = \frac{ 4} { y + 3} \)
    11. Solution

    7