Honors Algebra 2: Extra Practice on Solving Exponential Equations
- Class: Honors Algebra 2
- Author: Peter Atlas
- Algebra and Trigonometry: Structure and Method, Brown
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Solve:
- \( \displaystyle 2^{3x+5} = 8\)
Solution
\( \displaystyle -\frac{2}{3} \)
- \( \displaystyle 4^{x+1} = 8^{3x-5}\)
Solution
\( \displaystyle -\frac{17}{7} \)
- \( \displaystyle 3^{2x} \cdot 9^{x - 1} = 27^x \)
Solution
\( 2\)
- \( \displaystyle 5 \cdot 25^{2x+3} = 125^{4x - 1}\)
Solution
\( \displaystyle \frac{5}{4} \)
- \( \displaystyle 16 \cdot 8^{5x+2} = 32 \cdot 64^{x + 5}\)
Solution
\( \displaystyle \frac{25}{9} \)
- \( \displaystyle 2 \cdot 2^{x} \cdot 4^{x} = 512^{x - 8} \)
Solution
\( \displaystyle \frac{73}{6} \)
- \( \displaystyle 3 \cdot 4^{7x + 1} = 24 \)
Solution
\( \displaystyle \frac{1}{14} \)