Honors Algebra 2: Projectile Motion Extra Practice
- Class: Honors Algebra 2
- Author: Peter Atlas
- Algebra and Trigonometry: Structure and Method, Brown
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Recall that the height, in feet, of a projectile thrown upward from an initial height of h_{0} feet with an initial velocity of v_{0} feet per second is given by \( h(t) = -16t^2 + v_0 t + h_0\)
Simplify:
- A projectile is thrown up from the ground with an initial velocity of 48 feet per second.\( \displaystyle \)
- How high is the ball 1/3 of a second later? Answer to the nearest hundredth of a foot.
Solution
14.22 feet
- When does the ball hit the ground?
Solution
3 seconds
- When is the ball the highest?
Solution
1.5 seconds
- What's the highest the ball reaches?
Solution
36 feet
- When is the ball 50 feet high on the way down? Answer to the nearest tenth of a second
Solution
2.8 seconds
- A projectile is thrown up from an initial height of 30 feet with an initial velocity of 120 feet per second.
- How high is the ball 3/4 of a second later?
Solution
111 feet
- When does the ball hit the ground? Answer to the nearest tenth of a second.
Solution
7.7 seconds
- When is the ball the highest? Answer to the nearest hundredth of a second
Solution
3.75 seconds
- What's the highest the ball reaches?
Solution
255 feet
- When is the ball 50 foot high on the way up? Answer to the nearest hundredth of a second
Solution
0.17 seconds