Given
\( f(x) = \begin{cases} 3x - 7, & \text{if } x \leq 2 \\ 6 - 2x, & \text{if }x > 2 \end{cases}\) | \(g(x) = \begin{cases} 3x + 5, & \text{if } x < 5 \\ -x + 3, & \text{if } x \geq 5 \end{cases} \) | \( h(x) = \begin{cases} \displaystyle \frac{2}{3}x + 1, & \text{if } x < -3 \\ 2x - 3, & \text{if } x \geq -3 \end{cases} \) |